Lays of continuity

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Its been a pretty dry week for my blog but not in my life; its been at its most happening best! Sunday was my birthday. Monday was a lot of work. Tuesday and Wednesday were a lot of fun with my friend who was visiting me in UK. Thursday was sleeping for 12 hours as I hadn’t slept the previous two nights. And I don’t know what Friday will be like. Hmm. I haven’t had time to talk to Mom and Dad. I haven’t been mailing my friends (in fact one of my friends thought that I was upset with him or something like that and called up from India to enquire, hehe). I haven’t been having dinner and breakfast regularly and havent cooked in the whole of last week! So, by those standards, I guess no blogs being churned out is quite permissible.

Based on the nature of the facts above, I hypothesize that there exists an inverse relationship between the occurrences of events and the blogs written during the sample time window. But I’m pretty sure this is true. And can prove it too. In the following way. When the number of events increase, the time spent on them increases. As the amount of time in any stable system is constant, consequently, the time available for blogging reduces. Since the amount of time available is a determining factor for the number of blogs churned out, subsequently the number of blogs decrease. Therefore, it can be inferred that more eventful the week, lesser the blogs written during that time. Mathematically stated, if E= number of events in a given time period and B=number of blogs written during that time, then EB=k (where k is a constant). This is a universal rule that holds true for all lethargic instances of class homoSapiens. I am contesting the next Nobel Prize.
Shoo, I sound like a geek*!

Voila, jusqu'à la prochaine!





Addendum:
· A geek is defined as ‘A person who is single-minded or accomplished in scientific or technical pursuits but is felt to be socially inept’
· The title is adapted from the ‘Laws of continuity’ that my not-so-contemporary Bernoulli had once stated, that the discharge at each point in a pipe or channel is the same at every other point (assuming the there is no sink or source). Mathematically : Q1 = Q2 = A1 V1 = A2 V2.